Augists

Time O

31 May 2020

1 min read

时间复杂度O

1.线性阶



int i;

for (i = 0; i < n; ++i)
	;

2.对数阶



int i = 1;

while (i < n)
	i *= 2;

3.平方阶



int i, j;

for (i = 0; i < n; ++i)
{
	for (j = 0; j < n; ++j)
		;
}


int i, j;

for (i = 0; i < n; ++i)
{
	for (j = i; j < n; ++j)
		;
}